#### **UPDATE**

Actually I was suggesting my above answer to the people at geogebra.org and they told me about this nice parametric equation that only needs the center point and any 2 points on the ellipse, where A is the center:

#### f(t)=A+(B-A)*sin(t)+(C-A)*cos(t),

at 0 it equals C, at 1/2)*Pi it equals B, then at 2*pi back to C!

This one just wows me after as hard as I worked to figure out the one above...

And from that I derived this one:

#### f(t) = (1/2)*D+(1/2)*B+((1/2)*B-(1/2)*D)*sin(t)+(C-(1/2)*D-(1/2)*B)*cos(t)

Which given 3 points on the ellipse parameterizes it so that between B and D is the shorter axis...

please i need to draw minimum ellipse containing 3 points and the major axis must pass through origin .can you help me?

ReplyDeleteAh yeah I started putting my ideas in a different place a while back try this link: https://www.facebook.com/thurstonideas/photos/a.484355525088230.1073741827.484340751756374/518050615052054/?type=3&theater

ReplyDeleteI added to this page as well, that facebook page I linked has a lot of newer stuff too!

sorry that link isn't automatic

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